When graphing y = x2 – 14x + 24 and y = 20 – |x + 3|, which value would be the best minimum x- and minimum y-values for the viewing window so that all intercepts, minimums, maximums, and points of intersection are able to be seen as closely as possible?

–50
–45
–25
–20

At 25, all the important points will be in the graph-- barely. The vertex of the first equation is right at -25! So to be safe, it is better to go a bit larger.

If the viewing window is much larger, it is difficult to see small increments on the scale.

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josselynramosgarcia0 josselynramosgarcia0 · Answer 2 · 2020-11-02T19:39:03+01:00

josselynramosgarcia0 josselynramosgarcia0

02-11-2020

Answer:

-25

Step-by-step explanation:

on edge, i took the test

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When graphing y = x2 – 14x + 24 and y = 20 – |x + 3|, which value would be the best minimum x- and minimum y-values for the viewing window so that all intercepts, minimums, maximums, and points of intersection are able to be seen as closely as possible? –50 –45 –25 –20

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When graphing y = x2 – 14x + 24 and y = 20 – |x + 3|, which value would be the best minimum x- and minimum y-values for the viewing window so that all intercepts, minimums, maximums, and points of intersection are able to be seen as closely as possible?

–50
–45
–25
–20