Given:
Total number of students = 40
In the school ECA club, 3/8 of the students chose chess.
Of the students who chose chess, 4/5 also chose painting.
To find:
The number of student who chose both chess and painting.
Solution:
Total number of students = 40
3/8 of the students chose chess. So, number of students who chose chess is
[tex]\dfrac{3}{8}\times 40=15[/tex]
Of the students who chose chess, 4/5 also chose painting. So, number of students who chose both chess and painting is
[tex]\dfrac{4}{5}\times 15=12[/tex]
Therefore, 12 students chose both chess and painting.
