Two boats leave the same port at the same time. One travels at a speed of 28 mi/h in the direction N 50° E, and the other travels at a speed of 22 ml/h in a direction S 70° E (see the figure). How far apart are the two boats after 1 h? (Round your answer to the nearest mile.) ​

Two boats leave the same port at the same time One travels at a speed of 28 mih in the direction N 50 E and the other travels at a speed of 22 mlh in a directio class=

Respuesta :

After 1 hour, two boats will be at a distance of "25 miles".

Given:

  • One travel speed, [tex]a = 28 \ mi/h[/tex]
  • Other travel speed, [tex]b = 22 \ mi/h[/tex]
  • Angle, [tex]\Theta = 60^{\circ}[/tex]

As we know the formula,

→ [tex]Distance = \sqrt{a^2+b^2-2ab Cos \Theta}[/tex]

By substituting the values, we get

                  [tex]= \sqrt{(28)^2+(22)^2-2\times 28\times 22 Cos 60^{\circ}}[/tex]

                  [tex]= \sqrt{784+484-616}[/tex]

                  [tex]= \sqrt{652}[/tex]

                  [tex]= 25 \ miles[/tex]

Thus the above answer is correct.

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