Segment BH bisects angle ABC, the angle ABH =7x-5 and the angle CBH =3x+11. Find the angle of ABC

Answer:
[tex]angle \: abc = 46. \\ angle \: bac = 67. \\ angle \: acb = 67. \\ [/tex]
Step-by-step explanation:
[tex]angle \: ABH \: =7x - 5 \\ and \\ angle \: CBH =3x+11. \\ but \: ABH = CBH \\ so \: 7x - 5 = 3x + 11 \\ 4x = 16 \\ x = 4. \\ then \\7x - 5 = 23. \\ 3x+11 = 23.[/tex]