Answer:
5.5Ω
Explanation:
The circuit diagram shown is a parallel arrangement. To solve this problem for the equivalent resistance,
R1 = 10Ω
R2 = 20Ω
R3 = 30Ω
For circuits in parallel, equivalent resistance is ;
[tex]\frac{1}{Rt}[/tex] = [tex]\frac{1}{R1} + \frac{1}{R2} + \frac{1}{R3}[/tex]
Now insert the parameters and solve;
[tex]\frac{1}{Rt}[/tex] = [tex]\frac{1}{10} + \frac{1}{20} + \frac{1}{30}[/tex]
[tex]\frac{1}{Rt}[/tex] = [tex]\frac{6 + 3 + 2}{60}[/tex]
[tex]\frac{1}{Rt}[/tex] = [tex]\frac{11}{60}[/tex]
Rt = 5.5Ω
