Answer:
12[tex]x^{4}[/tex]y[tex]z^{7}[/tex]√3x
Step-by-step explanation:
2√108[tex]x^{9}[/tex]y²[tex]z^{14}[/tex]
so you will need two of something to take one out from under the squareroot
we can rewrite [tex]z^{14} = z^{7} *z^{7}[/tex] so we can take a [tex]z^{7}[/tex] out
we can rewrite y² as y*y so we can take a y out
we can rewrite [tex]x^{9}[/tex] as [tex]x^{4} *x^{4} *x[/tex] so we can take a [tex]x^{4}[/tex]out
for 108 think what is the smallest prime number that divides 108 and is 2
108= 2*54
same algorithm, smallest prime number that divides 54 is 2 so
108=2*2*27
same algorithm, smallest prime number that divides 27 is 3 so
108=2*2*3*9
we know 9 is 3*3 so
108=2*2*3*3*3 we can take out one 2 and one 3
put them all toghether now
2*2*3*[tex]x^{4}[/tex]*y*[tex]z^{7}[/tex]√3x = 12[tex]x^{4}[/tex]y[tex]z^{7}[/tex]√3x
