Respuesta :
Answer:
a) Amount saved if the interest is compounded annually is $5832
b) Amount saved if the interest is compounded semi-annually is $5849.5
Step-by-step explanation:
Principal Amount P = 5000
Time t = 10 years
Annual interest i = 8% = 0.08
We need to find amount saved if interest is compounded a) annually b) semi-annually
a) Amount saved if the interest is compounded annually
If interest compounded annually, n= 1
Using Formula: [tex]A=P(1+\frac{r}{n})^{nt}[/tex]
Putting values:
[tex]A=P(1+\frac{r}{n})^{nt} \\A=5000(1+\frac{0.08}{1})^{1*2}\\A=5000(1+0.08)^2\\A=5000(1.08)^2\\A=5000(1.1664)\\A=5832[/tex]
So, Amount saved if the interest is compounded annually is $5832
b) Amount saved if the interest is compounded semi-annually
If interest compounded semi-annually, n= 2
Using Formula: [tex]A=P(1+\frac{r}{n})^{nt}[/tex]
Putting values:
[tex]A=P(1+\frac{r}{n})^{nt} \\A=5000(1+\frac{0.08}{2})^{2*2}\\A=5000(1+0.04)^4\\A=5000(1.04)^4\\A=5000(1.1699)\\A=5849.5[/tex]
So, Amount saved if the interest is compounded semi-annually is $5849.5
(a). When compounded annually, the amount will be [tex]\$ 10,794.6[/tex]
(b). When compounded semi-annually, the amount will be [tex]\$ 10,955.6[/tex]
Compound interest:
It is given that, an individual saves $5000 in a bank account at the beginning of each year for 10 years.
[tex]Principal(P)=5,000, t=10 years, rate(r)=8\%[/tex]
As we know that,
[tex]Amount=P(1+\frac{r}{100} )^{t} \\\\Amount=5,000(1+\frac{8}{100})^{10} \\\\Amount=5,000*(\frac{108}{100})^{10}\\\\Amount=\$ 10,794.6[/tex]
When interest is compounded semi-annually;
[tex]r=8/2=4\%, t=10*2=20[/tex]
[tex]Amount=5,000(1+\frac{4}{100})^{20} \\\\Amount=5,000*(\frac{104}{100})^{20}\\\\Amount=\$ 10,955.6[/tex]
Learn more about the compound interest here:
https://brainly.com/question/24924853