Answer:
0.025 moles of NO₂ will produced
Explanation:
Given data:
Moles of NO₂ formed = ?
Volume of HNO₃ = 25.0 mL
Molarity of HNO₃ = 2 M
Solution:
Chemical equation:
Cu + 4HNO₃ → Cu(NO₃)₂ + 2NO₂ + 2H₂O
Number of moles of HNO₃:
Molarity = number of moles / volume in L
2M = number of moles / 0.025 L
Number of moles = 2 M × 0.025 L
Number of moles = 0.05 mol
Now we will compare the moles of HNO₃ with NO₂ from balance chemical equation.
HNO₃ : NO₂
4 : 2
0.05 : 2/4×0.05 =0.025
0.025 moles of NO₂ will produced.
