Answer:
Volume = 722.1 L
Explanation:
Given data:
Mass of gas = 902.0 g
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Volume of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will calculate the number of moles of C₂H₄.
Number of moles = mass/molar mass
Number of moles = 902.0 g/ 28.05 g/mol
Number of moles = 32.2 mol
Volume of gas:
PV = nRT
1 atm ×V = 32.2 mol × 0.0821 atm.L/ mol.K × 273.15 K
V = 722.1 atm.L/1 atm
V = 722.1 L
