Rewrite the function by completing the square
h(x)=4x^2+4x+1

Answer:
[tex]h(x) = 4(x+\frac{1}{2})^{2}[/tex]
Step-by-step explanation:
[tex]h(x)=4x^2+4x+1\\h(x)=4(x^2+x+\frac{1}{4}) \\h(x)=4(x^2+x+\frac{1}{4})\\h(x) = 4(x+\frac{1}{2})^{2}[/tex]