Respuesta :
Answer:
Let
y--------> cost of the dinner with friends
h--------> the number of hours Lindsay worked last week
we know that
y =\frac{1}{15} *( 10h+60)y=
15
1
∗(10h+60) ------> equation 11
y =\frac{1}{10} *( 10h)y=
10
1
∗(10h) ------> equation 22
equate equation 11 and equation 22
\begin{gathered} \frac{1}{15} *( 10h+60)=\frac{1}{10} *( 10h)\\\\ Multiply\ by\ 150\ both\ sides\\\\ 10*(10h+60)=15*10h\\\\ 100h+600=150h\\\\150h-100h=600\\\\ h=\frac{600}{50} \end{gathered}
15
1
∗(10h+60)=
10
1
∗(10h)
Multiply by 150 both sides
10∗(10h+60)=15∗10h
100h+600=150h
150h−100h=600
h=
50
600
h= 12\ hoursh=12 hours
therefore
the answer is
Lindsay worked 12\ hours12 hours last week
The equation that can be used to find the number of hours is
\frac{1}{15} *( 10h+60)=\frac{1}{10} *( 10h)
15
1
∗(10h+60)=
10
1
∗(10h)
Lindsay worked for about 120 hours last week.
What is an equation?
An equation is used to show the relationship between two or more variables and numbers.
Let h represent the number of hours Lindsay worked last week, hence:
(1/15)(10h + 600) = (1/10)(10h)
40h + 2400 = 60h
h = 120 hours
Lindsay worked for about 120 hours last week.
Find out more on Equation at: https://brainly.com/question/2972832