Respuesta :
Answer:
-12.38 N
Explanation:
This question requires you to first find the acceleration then apply Newton's 2nd law of motion to find the force.
To find deceleration use the formula;
v²= u²+2ad ---where
v= final speed = 0 m/s
u= initial speed = 3.0 m/s
a= acceleration { in this case , deceleration} = ?
d= distance from the point where its passenger rolled off= 4.0 m
therefore ;
[tex]a=\frac{v^2-u^2}{2d}[/tex]
[tex]a=\frac{0^2-3^2}{2*4} =\frac{-9}{8} m/s^2[/tex]
Mass of the sled is calculated from its weight force.
Weight force = mg
mass of sled = weight force / g where g= 10 m/s²
mass of sled = 110/10 = 11kg
The magnitude of horizontal net force will be : F= ma where ;
m= mass of sled = 11 kg
a= deceleration = -9/8 m/s²
F = 11 * -9/8 = -12.38 N
Force is acting on the opposite direction of the initial motion of the sled.
The magnitude of the horizontal net force acting on the sled is 12.375 N.
Given data:
The initial speed of sled is, u = 3.0 m/s.
The final speed of sled is, v = 0 m/s.
The distance covered before stopping is, s = 4.0 m.
The weight of sled is, W = 110 N.
Using the Newton's second law, the net horizontal force acting on the sled is given as,
F = ma
here,
m is the mass of sled.
a is the acceleration of sled.
Mass is calculated from the weight as,
W = mg
110 = m (10)
m = 11 kg.
Now, using the second kinematic equation of motion to obtain the acceleration of sled as,
[tex]v^{2}=u^{2}+2(-a)s\\\\0^{2}=3^{2}+2(-a)4\\\\8a=9\\\\a=1.125 \;\rm m/s^{2}[/tex]
Then the magnitude of net horizontal force is,
[tex]F = ma\\\\F = 11 \times 1.125\\\\F = 12.375\;\rm N[/tex]
Thus, we can conclude that the magnitude of the horizontal net force is 12.375 N.
Learn more about the Newton's second law here:
https://brainly.com/question/19860811