Answer:
+1
-1
Explanation:
The oxidation number of Na in NaCl is +1 and that of Cl is -1.
When NaCl is oxidized we have;
NaCl → Na⁺ + Cl⁻
In this process, Na will lose an electron to become Na⁺ and thus isoelectronic with Ne, Cl will gain the electrons to become Cl⁻ and thus isoelectronic with Argon.