Answer:
Step-by-step explanation:
to go from (4, 3/4 ) to (6, 0) you need
a line with slope m= (y2-y1)/(x2-x1) = [tex]\frac{3}{4}[/tex] -0 / 4-6 = [tex]\frac{3}{4} /\frac{-2}{1} =\frac{3}{4} *\frac{-1}{2} =\frac{-3}{8}[/tex]
use the quation of a line point-slope
(y-y1)=m(x-x1)
substitute m= -3/8 and (x1,y1) with (6,0)
[tex]y=\frac{-3}{8} (x-6)[/tex]
Now does point (10,4) where is the aim is verified by this equation?
substitute x=10, y=4 in the equation to check
4= -3(10-6)/8
4= -3*4/8
4=-3/2 this is never true so you do NOT make the shot
