Answer:
y-intercept: [tex]y=0[/tex]
axis of symmetry: [tex]x=0[/tex]
vertex: [tex](0,0)[/tex]
Step-by-step explanation:
To find the y-intercept, set x = 0 and solve for y.
I am assuming f(x) = y
[tex]y=4x^2[/tex]
[tex]y=4(0)^2[/tex]
[tex]y=0[/tex]
The y-intercept of the equation is y = 0.
Now, for the axis of symmetry, you need the equation [tex]x=\frac{-b}{2a}[/tex]
In an equation.. [tex]y=ax^2+bx+c[/tex]
In this case, there is only an a, so plug in the values into the equation.
[tex]x=\frac{0}{2(4)}[/tex]
[tex]x=0[/tex]
The axis of symmetry is x = 0.
To find the vertex, change the format of the equation from standard form to vertex form.
Vertex form: [tex]y=a(x-h)^2+k[/tex]
The vertex is [tex](h,k)[/tex]
[tex]y=4x^2 = 4(x+0)^2+0[/tex]
[tex](h,k)=(0,0)[/tex]
The vertex in this case is (0,0).
Graphing makes things a lot easier. If you can graph it, all you have to do is look at the graph and the answers are all there!
Hope this helped you!
