Answer:
66326.8 g Os
General Formulas and Concepts:
Chemistry - Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
Step 1: Define
2.1 × 10²⁶ atoms Os
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of Os - 190.2 g/mol
Step 3: Convert
[tex]2.1 \cdot 10^{26} \ atoms \ Os(\frac{1 \ mol \ Os}{6.022 \cdot 10^{23} \ atoms \ Os} )(\frac{190.2 \ g \ Os}{1 \ mol \ Os} )[/tex] = 66326.8 g Os
Step 4: Check
We are given 2 sig figs. Follow sig fig rules and round.
66326.8 g Os ≈ 66000 g Os
