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The sum of digits in a two-digit number is 14. If you double the reversed number and add the result to the original number, the sum would be 222. Find the original number

Respuesta :

Answer:

Original number is 86

Step-by-step explanation:

              Original:   10x + y

Double reversed:   2(10y + x)

Constraints:

  x + y = 14                                     ===>            x = 14 - y

  2(10y + x) + 10x + y = 222          ===>           21y + 12x = 222

Substitution to find y:

  21y + 12x = 222

  21y + 12(14 - y) = 222

  21y + 168 - 12y = 222

            9y + 168 = 222

                      9y = 54

                        y = 6

Substitution to find x:

  x = 14 - y

  x = 14 - 6

  x = 8

Original:   10x + y

                 10(8) + (6)

                 80 + 6

                 86

x = Tens place
y = Ones place
x+y=14
y=14-x
2(10y+x)+(10x+y)=222
20y+2x+10x+y=222
21y+12x=222
21(14-x)+12x=222
294-21x+12x=222
-9x = -72
x = 8
y = 14-8 =6
ANSWER: 86

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