The sum of three numbers is 17. The sum of twice the first number, 4 times the second number and 5 times the third number is 56. The difference between 7 times the first number and the second number is 41. Find the three numbers.

Respuesta :

Answer:

x=7  y=8  z=2

Step-by-step explanation:

Ver imagen butter1241

The value of all three numbers will be 7, 8, and 2  for the given condition.

How to form an equation?

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

In other words, an equation is a set of variables that are constrained through a situation or case.

Let's say the first number is x, the second is y and the third is z.

The sum of three numbers is 17 ⇒

x + y + x = 17

The sum of twice the first number, 4 times the second number and 5 times the third number is 56 ⇒

2x + 4y + 5z = 56

The difference between 7 times the first number and the second number is 41 ⇒

7x - y = 41 ⇒ y = 7x - 41

By substituting this y into the above equation.

A newly formed equation will be

-40x - 5z = -290

30x + 5z = 220

By solving them x = 7 and z = 2 by that y = 8

Hence all three values will be 7,2 and 8.

For more about the equation

https://brainly.com/question/10413253

#SPJ2