Find the value of c that completes the square

x^2-x+c

Please help me with how to do this, and show me. Thank you.

Respuesta :

Answer:

The value of c is 1/2

Step-by-step explanation:

We have to find the value of c that completes the square  [tex]x^2-x+c[/tex]

So, completing square is of form: [tex]a^2-2ab+b^2=(a-b)^2[/tex]

In the question given the value c can be found by breaking the middle term. we are given -x while the general formula is 2ab for middle term so, our c = 1/2 i.e 2(x)(1/2) we get x so, solving:

[tex]x^2-x+c\\=x^2-2(x)(\frac{1}{2})+(\frac{1}{2})^2-(\frac{1}{2})^2\\=(x-\frac{1}{2})^2-(\frac{1}{2})^2[/tex]

The value of c is 1/2