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A child of mass m is released from rest at the top of a water slide,
at height h=8.8 m above the bottom of the slide. Assuming that the slide
is frictionless because of the water on it, find the child’s speed at the bottom of the slide

Respuesta :

MubinaShazadi

Answer:

From the concept of energy conservation, Ei=Ef

Explanation:

mgh=1/2mv^2

=> v=

\sqrt{2gh}2gh

=

\sqrt{2 \times 9.8 \times 8.8}2×9.8×8.8

=

\sqrt{172.28}172.28

=13.12m/s.

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