Determine the vertex form of g(x) = x2 + 2x – 1. Which graph represents g(x)? On a coordinate plane, a parabola opens up. It goes through (negative 2, 3), has a vertex at (negative 1, 2), and goes through (0, 3). On a coordinate plane, a parabola opens up. It goes through (negative 1, 2), has a vertex at (1, negative 2), and goes through (3, 2). On a coordinate plane, a parabola opens up. It goes through (0, 3), has a vertex at (1, 2), and goes through (2, 3). On a coordinate plane, a parabola opens up. It goes through (negative 3, 2), has a vertex at (negative 1, negative 2), and goes through (1, 2).

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Answer:

the last one I think

Step-by-step explanation:

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The vertex form of the quadratic equation is:

[tex]g(x) = (x + 1)^2 - 2[/tex]

And the graph can be seen at the end

How to get the vertex form of the quadratic equation?

For a quadratic equation with leading coefficient a, and with vertex (h, k), the vertex form is:

[tex]y = a*(x - h)^2 + k[/tex]

Here we have:

[tex]g(x) = x^2 + 2x - 1[/tex]

First, we need to find the vertex. by using the known formula we get:

[tex]h = -2/(2*1) = -1[/tex]

To get the value of k, we need to evaluate g(x) in x = -1.

[tex]g(-1) = (-1)^2 + 2*-1 - 1 = 1 - 2 - 1 = -2[/tex]

So the vertex is (-1, -2), which means that the vertex form is:

[tex]g(x) = (x + 1)^2 - 2[/tex]

And its graph can be seen below.

If you want to learn more about quadratic equations:

https://brainly.com/question/1214333

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