Answer:
The equation of the line with slope = 4 and point (-5, -13)
will be:
Step-by-step explanation:
Given
As the point-slope form of the equation of line is
[tex]y-y_1=m\left(x-x_1\right)[/tex]
where m is the slope.
substituting the values m = 4 and the point (-5, -13)
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y-\left(-13\right)=4\left(x-\left(-5\right)\right)[/tex]
[tex]y+13=4\left(x+5\right)[/tex]
subtract 13 from both sides
[tex]y+13-13=4\left(x+5\right)-13[/tex]
[tex]y=4x+7[/tex]
Therefore, the equation of the line with slope = 4 and point (-5, -13)
will be:
[tex]y=4x+7[/tex]
