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Answer: 9 pounds of chocolate and 6 pounds of sugar candies
Let's define the variables:
C = pounds of chocolate candies used.
S = pounds of sugar candies used.
We know that he wants to make a total of 15lb, then:
C + S = 15
We also want that the price per pound to be equal to 5$.
This means that the price of the 15 pounds will be the same as the price of the un-mixed candies.
C*$7.00 + $2.00*S = $5.00*15
Then we have a system of equations:
C + S = 15
C*$7.00 + $2.00*S = $5.00*15
To solve this system, we need to start by isolating one of the variables, i will isolate C in the first equation:
C = 15 - S
now we can replace that in the other equation:
(15 - S)*$7.00 + $2.00*S = $5.00*15
Now we can solve this for S.
$105 - $5.00*S = $75
$105 - $75 = $5.00*S
$30 = $5.00*S
$30/$5 = S = 6
Then there are 6 pounds of sugar candy, and we can use the equation:
C + S = 15
C + 6 = 15
C = 15 - 6 = 9
There are 9 pounds of chocolate candy in the mix.
Step-by-step explanation:
By writing and solving a system of equations, we will see that the owner must use 6 lb of the chocolate candies and 9 lb of the sugar candies.
Let's define two variables:
- x = pounds of chocolate candies used
- y = pounds of sugar candies used.
Then, using the given information, we will have that:
x + y = 15
x*$7.00 + y*$2.00 = $5.00*15
If we isolate x in the first equation we get:
x = 15 - y
Now we can replace that in the second equation to get:
(15 - y)*$7.00 + y*$2.00 = $75
$105 - y*$5.00 = $75
$105 - $75 = y*$5.00
$30 = y*$5.00
$30/$5 = y = 6
So the owner must use 6 pounds of the chocolate candies, and the other 9 pounds of the sugar candies.
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