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If 8 g of a radioactive substance are present initially and 2 yr later only 4 g remain, how much of the substance will be present after 5 yrs?

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jaedyme9297

Answer:

none

Step-by-step explanation:

8-4=4

if every 2 years, 4 gallons disappear

then every 1 year, 2 gallons disappear

meaning that by 5 years there will be no substance left.

(5*2=10)

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