contestada

How many moles of Gold (III) sulfide must decompose to produce 4.32 moles of gold
metal given the reaction Au2S3 --> 2Au + 35

Respuesta :

Neetoo

Answer:

2.16 moles of Au₂S₃  are decomposed.

Explanation:

Given data:

Number of moles of gold (III) sulfide decomposed = ?

Number of moles of gold metal formed = 4.32 mol

Solution:

Chemical equation:

Au₂S₃      →       2Au + 3S

Now we will compare the moles of Au₂S₃ with  gold metal.

                            Au             :           Au₂S₃  

                             2              :                1

                            4.32         :             1/2×4.32 = 2.16    

2.16 moles of Au₂S₃  are decomposed.    

                           

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