If a ship travels north for 18 miles and east for 12 miles,
to the nearest tenth, approximately how far away is it
from it's starting point?

If a ship travels north for 18 miles and east for 12 miles to the nearest tenth approximately how far away is it from its starting point class=

Respuesta :

Answer:

The ship is approximately 21.6 miles away from its starting point

Step-by-step explanation:

∵ The North and the East are perpendicular

→ That means the distance between the starting position and

   the ending position shows a hypotenuse of a right triangle which

   its legs are the distances due to North and East

∵ The ship travels north for 18 miles

leg1 = 18 miles

∵ The ship travels east for 12 miles

leg2 = 12 miles

→ By using Pythagoras Theorem

(hypotenuse)² = (leg1)² + (leg2)²

∴ (hypotenuse)² = (18)² + (12)²

∴ (hypotenuse)² = 324 + 144

∴ (hypotenuse)² = 468

→ Take √  for both sides

∴ hypotenuse = 21.63330765

→ Approximate it to the nearest tenth

hypotenuse = 21.6 miles

∵ The hypotenuse of the right triangle represents the distance from

   the starting position to the ending position

The ship is approximately 21.6 miles away from its starting point