A 5 kg mass is oscillating on a spring with a time period of 2.8 seconds. What is the spring constant k of the spring?

Respuesta :

Answer:

k = 25.18 N/m

Explanation:

Simple Harmonic Oscillator

It consists of a weight attached to one end of a spring being allowed to move forth and back.

If m is the mass of the weight and k is the constant of the spring, the period of the oscillation is given by:

[tex]\displaystyle T=2\pi {\sqrt {\frac {m}{k}}}[/tex]

If the period is known, we can find the value of the constant by solving for k:

[tex]\displaystyle k=m\left(\frac{2\pi}{T}\right)^2[/tex]

Substituting the given values m=5 Kg and T=2.8 seconds:

[tex]\displaystyle k=5 \left(\frac{2\pi}{2.8}\right)^2[/tex]

k = 25.18 N/m