Answer:
see explanation
Step-by-step explanation:
Given
[tex]\frac{9}{a^2+9a+20}[/tex] , [tex]\frac{7a}{a^2+11a+28}[/tex]
Factor the denominators of both fractions
[tex]\frac{9}{(a+4)(a+5)}[/tex] , [tex]\frac{7a}{(a+4)(a+7)}[/tex]
The lowest common denominator of both fractions is (a + 4)(a + 5)(a + 7)
Multiply numerator/denominator of first fraction by (a + 7)
Multiply numerator/denominator of second fraction by (a + 5 )
[tex]\frac{9(a+7)}{(a+4)(a+5)(a+7)}[/tex] , [tex]\frac{7a(a+5)}{(a+4)(a+5)(a+7)}[/tex] , then
[tex]\frac{9a+63}{(a+4)(a+5)(a+7)}[/tex] , [tex]\frac{7a^2+35a}{(a+4)(a+5)(a+7)}[/tex]
