The y-intercept is: (0,1)
The domain is [tex]\{x|-\infty < x < \infty\}[/tex]
The horizontal asymptote is [tex]y = 0[/tex]
The given parameters from the complete question are:
[tex]f(x) = 2^{x-2}[/tex]
[tex]g(x) = f(x + 2)[/tex]
First, we calculate the function of g(x)
[tex]g(x) = f(x + 2)[/tex]
Calculate f(x + 2)
[tex]f(x) = 2^{x-2}[/tex]
[tex]f(x + 2) = 2^{x+2-2}[/tex]
[tex]f(x + 2) = 2^x[/tex]
So:
[tex]g(x) = 2^x[/tex]
Start by calculating the y intercept:
This means, we calculate the g(x) when [tex]x=0[/tex]
[tex]g(x) = 2^x[/tex]
[tex]g(0) = 2^0[/tex]
[tex]g(0) =1[/tex]
The above computation means (a) is incorrect; but (e) is correct.
Next, calculate the domain of g(x)
[tex]g(x) = 2^x[/tex]
Some features in a function that limit the x values are: roots, fractions, etc.
[tex]g(x) = 2^x[/tex] does not have any restricting value of x.
This means the value of x ranges from negative infinity to positive infinity.
Hence, the domain is: [tex](-\infty,\infty)[/tex]
The above computation means (b) is correct
Next, calculate the horizontal asymptote.
To do this, we plot the graph of g(x) --> see attachment
Then we trace a horizontal line from the horizontal part of the curve of g(x) till it gets to the y-axis.
From the attached graph of g(x), the line touches the y-axis at [tex]y = 0[/tex]
So, the horizontal asymptote is: [tex]y = 0[/tex]
Read more at:
https://brainly.com/question/8120140
