How many solutions does the system of equations below have? y = 3x + 2 Y-2x = 4 a) More than 1 solution b) At least 1 solution c) Exactly 1 solution d) No solution​

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Answer:

To determine how many solutions this system has, we must solve the system first. We start by using substitution to solve for x.

[tex]y = 3x + 2\\y - 2x = 4\\\\3x + 2 - 2x = 4\\\\x + 2 = 4\\\\x = 2[/tex]

Now we plug in what we found x back into one of the original equations to solve for y.

[tex]y = 3(2) + 2\\\\y = 6 + 2\\\\y = 8[/tex]

With this information we can now answer the question.

We can conclude that this system has C. exactly 1 solution, [tex](2, 8)[/tex].

The number of solutions does the system of equations is to be considered as the option c. Exactly 1 solution.

Calculation of the number of solution:

Since

y = 3x + 2

And, y - 2x = 4

So, we can write

3x + 2 -2x = 4

x + 2 = 4

x = 2

Now

y = 3(2) + 2

= 6 +  2

= 8

hence, The number of solutions does the system of equations is to be considered as the option c. Exactly 1 solution.

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