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A recent survey of people who eat salad suggest that 78% like tomatoes on their salad, 49% like cheese on their salad, and 36% like both tomatoes and cheese on their salad. Suppose a person who eats salad is selected at random, and find they like cheese on their salad. What is the probability that the person also likes tomatoes on their salad?

0.29
0.46
0.49
0.73

A recent survey of people who eat salad suggest that 78 like tomatoes on their salad 49 like cheese on their salad and 36 like both tomatoes and cheese on their class=

Respuesta :

Answer:

D) 0.73

Step-by-step explanation:

If we take the number of people liking cheese on their salad and divide it by the people who like both we get our result.

36%/49%

=

.36/.49

=

.73 or D

The conditional probability that the person also likes tomatoes on their salad is of 0.73.

What is Conditional Probability?

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which:

  • P(B|A) is the probability of event B happening, given that A happened.
  • [tex]P(A \cap B)[/tex] is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are given as follows:

  • Event A: Person likes cheese.
  • Event B: Person likes tomatoes.

Hence, the probabilities are given by:

[tex]P(A) = 0.49, P(A \cap B) = 0.36[/tex].

The conditional probability is given by:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.36}{0.49} = 0.73[/tex]

More can be learned about conditional probability at https://brainly.com/question/14398287

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