Answer:
[tex]d =2 \sqrt{10}[/tex]
General Formulas and Concepts:
Pre-Algebra
- Order of Operations: BPEMDAS
Algebra II
- Distance Formula: [tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Step-by-step explanation:
Step 1: Define
S (-5, -2)
T (-3, 4)
Step 2: Find distance d
- Substitute: [tex]d = \sqrt{(-3+5)^2+(4+2)^2}[/tex]
- Add: [tex]d = \sqrt{(2)^2+(6)^2}[/tex]
- Evaluate: [tex]d = \sqrt{4+36}[/tex]
- Add: [tex]d = \sqrt{40}[/tex]
- Simplify: [tex]d =2 \sqrt{10}[/tex]
