Answer:
The cannon has an initial speed of 13.25 m/s.
Explanation:
The launched cannonball is an example of a projectile. Thus, its launch speed can be determined by the application of the formula;
R = u[tex]\sqrt{\frac{2H}{g} }[/tex]
Where: R is the range of the projectile, u is its initial speed, H is the height of the cliff and g is the gravitaty.
R = 26.3 m, H = 19.3 m, g = 9.8 m/[tex]s^{2}[/tex].
So that:
26.3 = u[tex]\sqrt{\frac{2*19.3}{9.8} }[/tex]
[tex](26.3)^{2}[/tex] = [tex]u^{2}[/tex] x [tex]\frac{38.6}{9.8}[/tex]
691.69 = [tex]u^{2}[/tex] x [tex]\frac{38.6}{9.8}[/tex]
[tex]u^{2}[/tex] = [tex]\frac{691.69*9.8}{38.6}[/tex]
= [tex]\frac{6778.562}{38.6}[/tex]
[tex]u^{2}[/tex] = 175.6104
⇒ u = [tex]\sqrt{175.6104}[/tex]
= 13.2518
u = 13.25 m/s
The initial speed of the cannon is 13.25 m/s.
