Car's Initial velocity (u) = 5 m/s
Car's Final velocity (v) = 0 m/s (Stop)
Acceleration of the car (a) = -1.5 m/s²
Equation used to solve this problem:
[tex] \boxed{ \bf{ {v}^{2} = {u}^{2} + 2as}}[/tex]
By substituting values in the equation, we get:
[tex] \rm \longrightarrow {0}^{2} = {5}^{2} +2 \times ( - 1.5) \times s \\ \\ \rm \longrightarrow 0 = 25 - 3s \\ \\ \rm \longrightarrow 25 - 3s = 0 \\ \\ \rm \longrightarrow 25 - 25 - 3s =0 - 25 \\ \\ \rm \longrightarrow - 3s = - 25 \\ \\ \rm \longrightarrow 3s = 25 \\ \\ \rm \longrightarrow \dfrac{3s}{3} = \dfrac{25}{3} \\ \\ \rm \longrightarrow s = 8.3 \: m[/tex]
[tex] \therefore [/tex] Displacement of the toy car (s) = 8.3 m
