5) If I have 20 liters of gas at a temperature of 67 °C and a pressure of 88.89 atm, what will
be the pressure of the gas if I raise the temperature to 94 °C and decrease the volume to 12
liters?


6) I have an unknown volume of gas at a pressure of 0.50 atm and a temperature of 325 K.
If I raise the pressure to 900 torr, decrease the temperature to 320 K, and measure the final
volume to be 48 liters, what was the initial volume of the gas?


7) If I have 21 liters of gas held at a pressure of 78 atm and a temperature of 800 K, what
will be the volume of the gas if I decrease the pressure to 45 atm and decrease the temperature
to 750 K?


8) If I have 3.9 L of gas at a pressure of 5.0 atm and a temperature of 50.0°C, what will be
the temperature of the gas if I decrease the volume of the gas to 2.4 L and decrease the
pressure to 303.0 kPa?


9) I have an unknown volume of gas held at a temperature of 115 K in a container with a
pressure of 60.0 atm. If by increasing the temperature to 225 K and decreasing the pressure to
30.0 atm causes the volume of the gas to be 25 liters, how many liters of gas did I start with?

work too pls !! thank you so much !!!

Respuesta :

Answer:

Explanation:

We shall use gas law as follows

P₁ V₁ / T₁  = P₂ V₂ / T₂

5 ) V₁ = 20 , P₁ = 88.89 , T₁ = 273+ 67 = 340 K .

V₂ = 12 , P₂ = ? , T₂ = 273+ 94 = 367 K .

88.89 x 20 / 340 = P₂ x 12 / 367

P₂ = 159.9 atm .

6 )

V₁ = ? , P₁ = .5  , T₁  = 325 K .

V₂ = 48 , P₂ = 900/760 = 1.184  , T₂ = 320 K .

V₁ x .5 / 325 = 48 x 1.184 / 320

V₁ = 115.44 litres .

7 )  

V₁ = 21 , P₁ = 78 , T₁ = 800 K .

V₂ = ? , P₂ =45 , T₂ = 750 K .

21 x 78 / 800 = V₂ x 45 / 750

V₂ =  34.125 litres  .

8 )

V₁ = 3.9  , P₁ = 5 x 10⁵ Pa , T₁ = 323 K .

V₂ = 2.4 , P₂ =3.03 x 10⁵Pa , T₂ = ? .

3.9 x 5 x 10⁵ / 323 = 2.4 x 3.03 x10⁵ / T₂

T₂ =  120.45 K

=  -152.54⁰C .

9 )

V₁ = ?  , P₁ = 60  , T₁ = 115 K .

V₂ = 25 , P₂ =30 , T₂ = 225.

V₁ x 60 / 115 = 25 x 30 / 225

V₁ = 6.39 litre .