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2) A gas takes up a volume of 15 liters, has a pressure of 3.3 atm, and a temperature of
299 K. If I raise the temperature to 350 K and lower the pressure to 1050 mmHg, what is the
new volume of the gas?


3) A gas that has a volume of 28 liters, a temperature of 65 °C, and an unknown pressure
has its volume increased to 36 liters and its temperature decreased to 35 °C. If I measure the
pressure after the change to be 2.0 atm, what was the original pressure of the gas?

work too pls !!! thank you so much !!!

Respuesta :

Answer:

Explanation:

[tex]\frac{P1V1}{T} = \frac{P2V2}{T2} = \frac{3.3 *15}{299} = \frac{1050*V}{760*350}[/tex]

v= 41.9 L

b)  using the same formula as above [tex]P1= \frac{P2V2*T1}{T2 * V1}= \frac{36*2*338}{308*28} = 2.8 atm[/tex]

hope it helps

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