Answer:
so its 0.098*C
Explanation:
Let m gram be the mass of water.
Then potential energy of water is:
P.E.=mgh
=m×980×8400
Since potential energy is converted to kinetic energy
P.E.=K.E.
K.E.=m×980×8400
Half of kinetic energy is converted into heat.
Then heat energy:
Heat energy=
2
1
×m×980×8400
Convert joule into calories
heat=
4.2×10
7
m×980×4200
=m×0.098
But heat is:
Heat=msΔT
∴msΔT=m×0.098
m×1×ΔT=m×0.098
ΔT=0.098C
Rise in temperature of water is =0.098
∘
C .
