Answer:
V = 22.36 L
Explanation:
Given data:
Mass of oxygen = 18.0 g
Temperature = 350 K
Pressure = 0.720 atm
Volume of gas = ?
Solution:
Number of moles of oxygen :
Number of moles = mass/molar mass
Number of moles = 18.0 g/ 32 g/mol
Number of moles = 0.56 mol
Volume of oxygen:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
0.720 atm × V = 0.56 mol × 0.0821 atm.L/ mol.K × 350 K
V = 16.1 atm.L /0.720 atm
V = 22.36 L
