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A rope of negligible mass supports a block that weighs 30.0 N. as shown below. The maximum tension the rope can support without breaking is 50.0 N. What is the maximum
acceleration the weight can be pulled upwards with without breaking the rope? (Use g = 10 m/s)
WON

Respuesta :

lucic

Answer:

a = 6.7 m/s²

Explanation:

The formula to apply here is :

Mass * acceleration = Tension -weight

m*a = Ft -mg  -----where m is mass of block, a is acceleration , Ft  is force due to tension.

Given in the question that ;

Mass of block = 3 kg

Ft = 50 N

g= 10

m*a = Ft -mg

3*a = 50-30

3a= 20

a= 20/3

a= 6.7 m/s²

Cricetus

The maximum acceleration will be "6.7 m/s²".

Given:

  • m = 3 kg
  • Ft = 50 N
  • g = 10

By applying the formula,

→ [tex]Mass\times acceleration = Tension -weight[/tex]

or,

→                             [tex]ma = Ft-mg[/tex]

By substituting the values, we get

→                          [tex]3\times a = 50-30[/tex]

→                              [tex]3a = 20[/tex]

→                                [tex]a = \frac{20}{3}[/tex]

→                                [tex]a = 6.7 \ m/s^2[/tex]

Thus the above answer is right.

 

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