Amy, Justin, and Henry sent a total of 70 text messages during the weekend. Justin sent 10 fewer messages than Amy. Henry sent 2 times as many messages as Amy. How many messages did they each send?

Respuesta :

Answer:

justin 10+ Amy 20 + henry 40+ do answer would be 10+20+50=70

explanation

I took justin and timed it by two then half of 20 is 10 then timed it by two again which 20*2 is 40

add it all together and you get 70

Amy sent 20 messages, Justin 10 messages and Henry 40 messages in total.

System of equations

These type of equation consists of equation with unknown variables.

Let the number of messages sent by amy be x

Let the number of messages sent by Justin be y

Let the number of messages sent by Henry be z

If the total number od mesages sent is 70, hence;

x + y + z = 70

If Justin sent 10 fewer messages than Amy, then;

y = x - 10

If Henry sent 2 times as many messages as Amy, then;

z= 2x

Substitute

x + x - 10 + 2x = 70

4x = 70 + 10

4x = 80

x = 20

Recall

y = x  - 10

y = 10

Also z = 2x

z = 2(20)
z = 40

Hence Amy sent 20 messages, Justin 10 messages and Henry 40 messages in total.

Learn more on system of equation here: https://brainly.com/question/13729904

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