Answer :-
[tex]\odot [/tex][tex]\sf {\dfrac {-1}{3}}[/tex]
[tex]{\bigcirc}[/tex]0
[tex]\bigcirc [/tex][tex]\sf {\dfrac {-2}{3}}[/tex]
[tex]\bigcirc [/tex][tex]\sf {\dfrac {1}{3}}[/tex]
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Calculations:-
Let's understand the concept:-
- Here for solution We need to find Value of a first .
- Then we can find the required value.
Solution:-
- First write the given equation
[tex]\longrightarrow[/tex][tex]\sf {\dfrac {a}{4}}={\dfrac {2}{3}}[/tex]
- Use cross multiplication method
[tex]\longrightarrow[/tex][tex]\sf 3a=2×4 [/tex]
[tex]\longrightarrow[/tex][tex]\sf 3a=8 [/tex]
- Now interchange both sides and get a
[tex]\longrightarrow[/tex][tex]\sf a={\dfrac {8}{3}}[/tex]
Now,
- Substitute the values in the equation
[tex]\longrightarrow[/tex][tex]\sf {\dfrac {a-4}{4}}[/tex]
[tex]\longrightarrow[/tex][tex]\sf {\dfrac {{\dfrac {8}{3}}-4}{4}}[/tex]
[tex]\longrightarrow[/tex][tex]\sf ({\dfrac {8}{3}}-4)\times {\dfrac {1}{4}}[/tex]
[tex]\longrightarrow[/tex][tex]\sf ({\dfrac {8-12}{3}})\times{\dfrac{1}{4}}[/tex]
[tex]\longrightarrow[/tex][tex]\sf {\dfrac {{\cancel{-4}}}{3}}\times {\dfrac {1}{{\cancel{4}}}}[/tex]
[tex]\longrightarrow[/tex][tex]\sf {\dfrac {-1}{3}}[/tex]
[tex]\therefore[/tex][tex]{\underline{\boxed{\bf {\dfrac {(a-4)}{4}}={\dfrac {-1}{3}}}}}[/tex]
