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In a laboratory, bunsen burner is used to increase the temperature of lime from 10 °C to 50 °C with the thermal energy of 80000 J. If the mass of the lime is 20 kg the specific heat capacity of the lime would be a 50 J/g C b 100 J/g C c 75 J/g C d 25 J/g C

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Neetoo

Answer:

c = 100 J/g.°C

Explanation:

Given data:

Mass of lime = 20 g

Heat absorbed = 80,000 J

Initial temperature = 10°C

Final temperature = 50°C

Specific heat capacity of lime = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 50°C - 10°C

ΔT = 40°C

80,000 J = 20 g×c×40°C

80,000 J = 800°C×c

c = 80,000 J /800g.°C

c = 100 J/g.°C

The specific heat capacity of the lime would be  is  c = 100 J/g.°C

  • The calculation is as follows:

The following formula should be used:

Q = m.c. ΔT

here

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now

ΔT = 50°C - 10°C

= 40°C

So,

80,000 J = 20 g×c×40°C

80,000 J = 800°C×c

c = 100 J/g.°C

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