NEED HELP ASAP
Let u = ⟨9, –2⟩, v = ⟨–4, 3⟩, and w = ⟨5, 1⟩. Kelcy incorrectly determined 3u – 5(v + w) to be ⟨32, –26⟩. Review her steps as shown.

3u – 5(v + w)

3⟨9, –2⟩ – 5[⟨–4, 3⟩ + ⟨5, 1⟩]

⟨27, –6⟩ – 5[⟨–1, 4⟩]

⟨27, –6⟩ + ⟨5, –20⟩

⟨32, –26⟩

What mistake did Kelcy make?

She added ⟨–4, 3⟩ and ⟨5, 1⟩ incorrectly.
She did not correctly distribute 3 to both components of u.
She should have distributed –5 to both v and w before adding.
She should have subtracted ⟨27, –6⟩ and ⟨5, –20⟩, rather than adding.

Respuesta :

Answer:

A

Step-by-step explanation:

-4 +5 is 1 not -1 lol

The incorrect step where Kelcy did mistake is given by: Option A: She added ⟨–4, 3⟩ and ⟨5, 1⟩ incorrectly.

How to add two vectors?

Suppose that two vectors are given as:

[tex]x = \: < a,b > \\y= \: < c,d >[/tex]

Then, their addition is given as:

[tex]x + y = \: < a +c , b + d >[/tex]

For this case, we can see that when Kelcy added <-4,3 > and <5,1>, she didn't add -4 and 5 correctly, as it results in +1, and not -1,

Thus, <-4,3> + <5,1> = <1,4>

Thus, wrong addition caused error in the solution.

Thus, the incorrect step where Kelcy did mistake is given by: Option A: She added ⟨–4, 3⟩ and ⟨5, 1⟩ incorrectly.

Learn more about addition of vectors here:

https://brainly.com/question/4553385