Answer:
The question, in the slope-intercept form will be:
Step-by-step explanation:
Taking the two points on the line to find the slope
(0, 0)
(4, 4)
[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\left(x_1,\:y_1\right)=\left(0,\:0\right),\:\left(x_2,\:y_2\right)=\left(4,\:4\right)[/tex]
[tex]m=\frac{4-0}{4-0}[/tex]
[tex]m=1[/tex]
As the point-slope form is
[tex]y-y_1=m\left(x-x_1\right)[/tex]
where m is the slope
substituting the values m = 1 and the point (0, 0)
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y-0=1(x-0)[/tex]
[tex]y=x[/tex]
As the slope-intercept form is
[tex]y=mx+b[/tex]
where m is the slope and b is the y-intercept
so writing the equation in slope-intercept form
[tex]y=x[/tex]
[tex]y=1(x)+0[/tex]
Therefore, the question, in the slope-intercept form will be:
