Answer:
Two-electron.
Explanation:
Hello!
In this case, since the half-reaction by which chlorine is reduced to aqueous chloride ion is:
[tex]Cl^0_2\rightarrow 2Cl^-[/tex]
We can see each chlorine undergo a decrease of electrons by 1, it means that, since there are two chlorine atoms undergoing an electron decrease, we write:
[tex]Cl^0_2+2e^-\rightarrow 2Cl^-[/tex]
Which means this is a two-electron process.
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