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2.1.2 Linear Tables and Graphs (Algebra 1)
The question is on the image below

212 Linear Tables and Graphs Algebra 1 The question is on the image below class=
212 Linear Tables and Graphs Algebra 1 The question is on the image below class=

Respuesta :

Answer:

Step-by-step explanation:

1). Let the equation of a line is,

   y = mx + b

   Here, m = slope of the line

   b = y-intercept

   From the graph attached,

   Slope = [tex]\frac{\text{Rise}}{\text{Run}}[/tex] = [tex]\frac{1}{4}[/tex]

   y-intercept = -2

   Equation → y = [tex]\frac{1}{4}x-2[/tex]

2). Slope of the line = [tex]\frac{\text{Rise}}{\text{Run}}=\frac{3}{4}[/tex]

   y-intercept 'b' = -3

   Equation → y = [tex]\frac{3}{4}x-4[/tex]

3). Slope of the line = [tex]\frac{\text{Rise}}{\text{Run}}=\frac{-5}{0.75}[/tex]

                                 = [tex]-\frac{20}{3}[/tex]

    y-intercept = 5

    Equation → y = [tex]-\frac{20}{3}+5[/tex]

4). Slope of the line = [tex]\frac{\text{Rise}}{\text{Run}}=\frac{-2}{4}=-\frac{1}{2}[/tex]

    y-intercept = 4

    Equation → y = [tex]-\frac{1}{2}x+4[/tex]

5). Since, line is passing through origin (0, 0)

    y-intercept = 0

    Slope = [tex]\frac{\text{Rise}}{\text{Run}}=\frac{1}{1}[/tex]

    Equation → y = x

6). Slope of the line = [tex]\frac{\text{Rise}}{\text{Run}}=\frac{1}{4}[/tex]

    y-intercept = -4

    Equation → y = [tex]\frac{1}{4}x-4[/tex]