Answer:
0.805 M.
Explanation:
Hello!
In this case, since the molarity of a solution is computing by dividing the moles of solute over the volume of solution in liters (M=n/V), for 15.0 g of potassium chloride (74.55 g/mol) we compute the corresponding moles:
[tex]n=15.0gKCl*\frac{1molKCl}{74.55gKCl}=0.201molKCl[/tex]
Next, since the volume is 0.2500 in liters, the molarity turns out:
[tex]M=\frac{0.201mol}{0.2500L} \\\\M=0.805M[/tex]
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