Respuesta :
Complete Question:
A purse at radius 2.00 m and a wallet at radius 3.00 m travel in uniform circular motion on the floor of a merry-go-round as the ride turns.
They are on the same radial line. At one instant, the acceleration of the purse is (2.00 m/s2 ) i + (4.00 m/s2 ) j .At that instant and in unit-vector notation, what is the acceleration of the wallet
Answer:
aw = 3 i + 6 j m/s2
Explanation:
- Since both objects travel in uniform circular motion, the only acceleration that they suffer is the centripetal one, that keeps them rotating.
- It can be showed that the centripetal acceleration is directly proportional to the square of the angular velocity, as follows:
    [tex]a_{c} = \omega^{2} * r (1)[/tex]
- Since both objects are located on the same radial line, and they travel in uniform circular motion, by definition of angular velocity, both have the same angular velocity ω.
    ∴ ωp = ωw (2)
      ⇒ [tex]a_{p} = \omega_{p} ^{2} * r_{p} (3)[/tex]
        [tex]a_{w} = \omega_{w}^{2} * r_{w} (4)[/tex]
- Dividing (4) by (3), from (2), we have:
    [tex]\frac{a_{w} }{a_{p}} = \frac{r_{w} }{r_{p}}[/tex]
- Solving for aw, we get:
    [tex]a_{w} = a_{p} *\frac{r_{w} }{r_{p} } = (2.0 i + 4.0 j) m/s2 * 1.5 = 3 i +6j m/s2[/tex]