A line has a slope of Negative three-fourths and passes through the point (–5, 4). Which is the equation of the line?
y = negative three-fourths x + one-fourth
y = negative three-fourths x + 4
y = negative three-fourths x minus 2
y = negative three-fourths x minus one-fourth

Respuesta :

Answer:

3X+4Y-1=0

Step-by-step explanation:

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The answer is A. y=-3/4x+1/4