A 6.0 kg object is pushed with a force of 12 N. If the mass of the object is cut in half to 3.0 kg, what happens to the acceleration if the force remains constant?

Respuesta :

Answer:

aceleration doubles

Explanation:

From Newton's secon law, one has

F=m*a

where F is the force, m the mass and a the aceleration.

In general, if m becomes m/2, in order to have the same force,

the acceleration must be doubled:

[tex]F=m*a=\frac{m}{2} (2*a)[/tex]

In our particular case,

[tex]12=6*a=\frac{6}{2} (2*a)\\12=3(2*a)[/tex]

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